j^2+22j+212=0

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Solution for j^2+22j+212=0 equation:


Simplifying
j2 + 22j + 212 = 0

Reorder the terms:
212 + 22j + j2 = 0

Solving
212 + 22j + j2 = 0

Solving for variable 'j'.

Begin completing the square.

Move the constant term to the right:

Add '-212' to each side of the equation.
212 + 22j + -212 + j2 = 0 + -212

Reorder the terms:
212 + -212 + 22j + j2 = 0 + -212

Combine like terms: 212 + -212 = 0
0 + 22j + j2 = 0 + -212
22j + j2 = 0 + -212

Combine like terms: 0 + -212 = -212
22j + j2 = -212

The j term is 22j.  Take half its coefficient (11).
Square it (121) and add it to both sides.

Add '121' to each side of the equation.
22j + 121 + j2 = -212 + 121

Reorder the terms:
121 + 22j + j2 = -212 + 121

Combine like terms: -212 + 121 = -91
121 + 22j + j2 = -91

Factor a perfect square on the left side:
(j + 11)(j + 11) = -91

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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